x² + 10x = 3 α + β = 10.x1 + 10.x2 = 10 (x1 + x2) = 10 .( - b/a) = 10 (- 10/1) = - 100 α .β = (10.x1) . (10.x2) = 100 .x1 .x2 = 100 (c/a) = 100 (-3/1) = - 300 bentuk umum persamaan baru x² - (α + β)x + α.β = 0 x² - (-100)x + (-300) = 0 x² + 100x - 300 = 0 |