The distance between two bodies is doubled. How is the magnitude of the gravitational force between them affected? Force of gravity: `F = (Gm_1m_2)/r^2` It is given that r2 = 2r1 `:.F_2/F_1 = r_1^2/r_2^2 = r_1^2/(4r_1^2) = 1/4` `:. F_2 = 1/4 F_1` Therefore, the force of gravity is reduced four times. Concept: Centre of Gravity Is there an error in this question or solution? |