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Given: Equation 1: x + y = 4 Equation 2: 2x + ky = 3 Both the equations are in the form of : a1x + b1y = c1 & a2x + b2y = c2 where a1 & a2 are the coefficients of x b1 & b2 are the coefficients of y c1 & c2 are the constants For the system of linear equations to have no solutions we must have ………(i) According to the problem: a1 = 1 a2 = 2 b1 = 1 b2 = k c1 = 4 c2 = 3 Putting the above values in equation (i) we get: ⇒ k = 2Also we findThe value of k for which the system of equations has no solution is k = 2 |