When the digits of a two digit number are reversed The new number is 18 more than the original number?

The number will have digits: xy ~ where x is the tens place, y is the ones place Number is: 10x + y The sum of the digits of a two-digit numeral is 8. x + y = 8 If the digits are reversed, the new number is 18 greater than the original number. 10y + x = 18 + 10x + y y - x = 2 Now, we have: x + y = 8 y - x = 2 Substitute using: y - x = 2 or y = 2 + x x + y = 8 x + 2 + x = 8 2x = 6 x = 3 Substitute again: y = 2 + x y = 2 + 3 y = 5

Number is: 10x + y = 10*3 + 5 = 35