When an electron in hydrogen atom is excited from its 3rd to 5th stationary orbit, tbe change in angular momentum of electron is (Planck's constant: h = 6.62 x 10-34 Js) ____________.
When an electron in hydrogen atom is excited from its 3rd to 5th stationary orbit, tbe change in angular momentum of electron is 2.11 x 10-34 Js. Explanation: Change in the angular momentum, `Delta "L" = "L"_2 - "L"_1 = ("n"_2 "h")/(2 pi) - ("n"_1 "h")/(2 pi)` `therefore Delta "L" = "h"/(2pi) ("n"_2 - "n"_1)` `= (6.62 xx 10^-34)/(2 xx 3.14) (5 - 3)` `= 2.11 xx 10^-34 "Js"` Concept: Bohr’s Atomic Model Is there an error in this question or solution? To view explanation, please take trial in the course below. NEET 2023 - Target Batch - Aryan Raj Singh To view explanation, please take trial in the course below. NEET 2023 - Target Batch - Aryan Raj Singh Please attempt this question first. Add Note More ActionsUh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now |