What is the smallest 4 digit number which when divided by 6 8 and 9 leaves remainder 5 in each case?

Find the largest four digits number which when divided by 4, 7 and 13 leaves a remainder of 3 in each case.

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Find the greatest six digit number which, when divided by 6,7,8,9 and 10 , gives 4,5,6,7 and 8 respectively as remainders.

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What is the smallest 4 digit number which when divided by 6 8 and 9 leaves remainder 5 in each case?

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100 Questions 100 Marks 90 Mins

Given,

The given numbers are 2, 3, 4 and 6.

Concept:

The smallest four-digit number is 1000.

Calculation:

LCM of 2, 3, 4 and 6 = 2 × 2 × 3 = 12

When we divide 1000 by 12 we get 4 as the remainder.

The smallest four-digit number which is divisible by 2, 3, 4 and 6 is = 1000 – 4 + 12 = 1008

The smallest four-digit number which when divided by 2, 3, 4 and 6 leaves remainder 1 in each case = 1008 + 1 = 1009

∴ The number will be 1009.

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