Two circles of 6 cm each intersect each other

Two circles of 6 cm each intersect each other

Two circles of 6 cm each intersect each other
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Question 12 Circles Exercise 12A

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Two circles of 6 cm each intersect each other

Answer:

It is given that

OA = 10cm and AB = 12 cm

So we get

AD = ½ × AB

By substituting the values

AD = ½ × 12

By division

AD = 6cm

Consider △ ADO

Using the Pythagoras theorem

OA^2 = AD^2 + OD^2

By substituting the values we get

10^2 = 6^2 + OD^2

On further calculation

OD^2 = 10^2 - 6^2

So we get

OD^2 = 100 – 36

By subtraction

OD^2 = 64

By taking the square root

OD = √64

So we get

OD = 8cm

We know that O’A = 8cm

Consider △ ADO’

Using the Pythagoras theorem

O’A^2 = AD^2 + O’D^2

By substituting the values we get

8^2 = 6^2 + O’D^2

On further calculation

O’D^2 = 8^2 - 6^2

So we get

O’D^2 = 64 – 36

By subtraction

O’D^2 = 28

By taking the square root

O’D = √28

We get

O’D = 2 √7

We know that

OO’ = OD + O’D

By substituting the values

OO’ = (8 + 2 √7) cm

Therefore, the distance between their centres is (8 + 2 √7) cm.

Two circles of 6 cm each intersect each other

Two circles of 6 cm each intersect each other

Two circles may intersect in two imaginary points, a single degenerate point, or two distinct points.

The intersections of two circles determine a line known as the radical line. If three circles mutually intersect in a single point, their point of intersection is the intersection of their pairwise radical lines, known as the radical center.

Two circles of 6 cm each intersect each other

Let two circles of radii

Two circles of 6 cm each intersect each other
and and centered at
Two circles of 6 cm each intersect each other
and
Two circles of 6 cm each intersect each other
intersect in a region shaped like an asymmetric lens. The equations of the two circles are

Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other

Combining (1) and (2) gives

Two circles of 6 cm each intersect each other

Multiplying through and rearranging gives

Two circles of 6 cm each intersect each other

Solving for results in

Two circles of 6 cm each intersect each other

The chord connecting the cusps of the lens therefore has half-length

Two circles of 6 cm each intersect each other
given by plugging back in to obtain

Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other

Solving for

Two circles of 6 cm each intersect each other
and plugging back in to give the entire chord length
Two circles of 6 cm each intersect each other
then gives

Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other

This same formulation applies directly to the sphere-sphere intersection problem.

To find the area of the asymmetric "lens" in which the circles intersect, simply use the formula for the circular segment of radius

Two circles of 6 cm each intersect each other
and triangular height
Two circles of 6 cm each intersect each other

Two circles of 6 cm each intersect each other

twice, one for each half of the "lens." Noting that the heights of the two segment triangles are

Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other

The result is

Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other

The limiting cases of this expression can be checked to give 0 when

Two circles of 6 cm each intersect each other
and

Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other
Two circles of 6 cm each intersect each other

when

Two circles of 6 cm each intersect each other
, as expected.

Two circles of 6 cm each intersect each other

In order for half the area of two unit disks (

Two circles of 6 cm each intersect each other
) to overlap, set
Two circles of 6 cm each intersect each other
in the above equation

Two circles of 6 cm each intersect each other

and solve numerically, yielding

Two circles of 6 cm each intersect each other
(OEIS A133741).

Two circles of 6 cm each intersect each other

If three symmetrically placed equal circles intersect in a single point, as illustrated above, the total area of the three lens-shaped regions formed by the pairwise intersection of circles is given by

Two circles of 6 cm each intersect each other

Two circles of 6 cm each intersect each other

Similarly, the total area of the four lens-shaped regions formed by the pairwise intersection of circles is given by

Two circles of 6 cm each intersect each other

Borromean Rings, Brocard Triangles, Circle-Ellipse Intersection, Circle-Line Intersection, Circular Segment, Circular Triangle, Double Bubble, Goat Problem, Johnson's Theorem, Lens, Lune, Mohammed Sign, Moss's Egg, Radical Center, Radical Line, Reuleaux Triangle, Sphere-Sphere Intersection, Steiner Construction, Triangle Arcs, Triquetra, Venn Diagram, Vesica Piscis Sloane, N. J. A. Sequence A133741 in "The On-Line Encyclopedia of Integer Sequences."

Weisstein, Eric W. "Circle-Circle Intersection." From MathWorld--A Wolfram Web Resource. https://mathworld.wolfram.com/Circle-CircleIntersection.html

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