You can put this solution on YOUR website! There are  Four of these cards are kings. Therefore the probability of drawing a After drawing The probability of drawing = = = so, your answer is b)
Option 1 : \(\frac{1}{{17}}\)
10 Questions 10 Marks 10 Mins
Concept \({\bf{C}}\left( {{\bf{n}},\;{\bf{r}}} \right) = \frac{{{\bf{n}}!}}{{{\bf{r}}!\left( {{\bf{n}} - {\bf{r}}} \right)!}}\) Calculation From 52 cards, 2 can be chosen in C(52, 2) ways. There are 4 suits in a deck of 52 cards and each number is present in all the 4 suits. There are 13 numbers form 1(Ace card) to 13(King card). If we consider the number 1, then from 4 Aces, 2 can be chosen in C(4, 2) ways. There are 13 numbers in total so, total ways in which two same numbers can be chosen is 13 × C(4, 2) Required probability \( = \frac{{13\; \times \;{\rm{C}}\left( {4,{\rm{\;}}2} \right)}}{{{\rm{C}}\left( {52,{\rm{\;}}2} \right)}}\) \(= \frac{{13\; \times \;12}}{{52\; \times \;51}}\) \(= \frac{1}{{17}}\) Correct option is (1). India’s #1 Learning Platform Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes Trusted by 3.3 Crore+ Students |
Two cards are chosen at random from a deck of 52 playing cards. what is the probability that they
Pos Terkait
Copyright © 2024 ketajaman Inc.
