The minimum phase difference between two SHM

The amplitude of SHM

Two particles A and B execute simple harmonic motion of period T and 5T/4. They start from mean position. The phase difference between them when the particle A complete an oscillation will be

A particle executes simple harmonic motion with a time period of 16 s. At time t = 2 s, the particle crosses the mean position while at t = 4s, velocity is

The amplitude of motion in metre is

The displacement equation of a simple harmonic oscillator is given by

The amplitude of the oscillator will be

The motion of a particle varies with time according to the relation

Two particles execute SHM of the same amplitude and frequency along the same straight line. If they pass one another when going in opposite directions, each time their displacement is half their amplitude, the phase difference between them is

Two simple harmonic motions are represented by the equations

The phase difference of the velocity of particle 1, with respect to the velocity of particle 2 is

A particle is undergoing a one dimensional simple harmonic oscillation of amplitude

about the origin on X-axis with time period T and is at

at. What is the position of the particle after a time interval t = 3.15T ?

The displacement of a particle performing simple harmonic motion is given by,

where distance is in cm and time is in second. The amplitude of motion is

Q10

The displacement-time graph of a particle executing SHM is as shown in the figure.

The corresponding force-time graph of the particle is