The least multiple of 13 which when divided by 4, 5, 6, 7 leaves remainder 3 in each case is

The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is : [A]840 [B]842 [C]2520 [D]2522

2522 LCM of 4, 5, 6, 7 and 8 = 840. Let require number be 840 K + 2 which is multiple of 13. Least value of K for which (840 K + 2) is divisible by 13 is K = 3 ∴ Require Number = 840 $latex \times$ 3 + 2 = 2520 + 2 = 2522.

Hence option [D] is correct answer.