Power P is related to distance x and time t as P b at x 2 at the dimensional formula of b is

Answer

लिखित उत्तर

Solution : The given equation can be written as, `Pat = b-x^(2)` <br> Now, ` [Pat] = [b] =[ x^(2)]` or`[b]=[ x^(2)] = [M^(0)L^(2)T^(0)]` <br> and ` [a] = ([x^(2)])/([Pt]) ([L^(2)])/([ML^(2)T^(-3)][T]) = [M^(-1)L^(0)T^(0)]`

Text Solution

Solution : The given equation can be written as, <br> `Pat=b-x^(2)` <br> Now, `[Pat]=[b]=[x^(2)]` <br> or `[b]=[x^(2)]=[M^(0)L^(2)T^(0)]` <br> and `[a]=([x^(2)])/([Pt])=([L^(2)])/([ML^(2)T^(-3)][T])=[M^(-1)L^(0)T^(2)]`

Text Solution

Solution : The given relation is `P =(b -x^2)/(at)` <br> As `x^2` is subtracted from b, therefore, the <br> dimensions of are of `x^2, i.e., b= [L^2]` <br> we can rewrite relation (i) as `P = (L^2)/(at)` <br> or `a= (L^2)/(Pt) = (L^2)/([ML^2 T^(-3)] [T]) =[M^(-1)L^0T^2]`