more math problems » 11) The LCM of two numbers is 8919, and their sum is 1000. The two numbers are:
Answer: C Explanation: Let the two numbers be x and (1000 - x) ∴ x * (1000 - x) = 8919 (x - 991) (-x + 9) = 0 ∴ (x - 991) = 0 X = 991, and (-x + 9) = 0 -x = -9 X = 9 So, the required numbers are 991 and 9. 12) If the LCM of two numbers is 70 and their HCF is 2, find the numbers.
Answer: D Explanation: Apply Formula: HCF x LCM = First number x Second number 2 x 70 = 140 (product of two numbers) The option D satisfies the given condition, as 14 * 10 = 140. So, the required numbers are 14 and 10. 13) Three different containers contain 496 liters, 403 liters, and 713 liters of water, respectively. What is the capacity of the biggest container that can measure three different quantities evenly?
Answer: C Explanation: For the capacity of the biggest container, we have to find the HCF. HCF: By Long Division method First find the HCF of two numbers, 496 and 403 The HCF of 496 and 403 = 31 HCF of 713 and 31 is 31 14) The least number which when divided by 2, 3, 4, 5 and 6 leaves the same remainder 1 in each case. If the same number is divided by 7, it leaves no remainder. Find the number.
Answer: B Explanation: LCM of 2, 3, 4, 5, 6 LCM = 2 x 2 x 3 x 5 = 60 Now, 60 x 1 + 1 = 61 is not divisible by 7 60 x 2 + 1 = 121 is not divisible by 7 60 x 5 + 1 = 301 is divisible by 7 Hence 301 is the number. 15) Which is the greatest three-digit number which when divided by 6, 9 and 12 leaves a remainder of 3 in each case?
Answer: A Explanation: Greatest three digit number = 999 LCM = 2 x 2 x 3 x 3 = 36 On dividing 999 by 36, Remainder = 27. ∴ The greatest three digit number divisible by 6, 9, and 12 = (999 - 27) = 972 As per the question, the required number is (972 + 3) = 975. H.C.F and L.C.M Aptitude Test Paper 1 H.C.F and L.C.M Aptitude Test Paper 2 H.C.F and L.C.M Aptitude Test Paper 4 H.C.F and L.C.M Aptitude Test Paper 5 H.C.F and L.C.M Aptitude Concepts Next TopicH.C.F and L.C.M Aptitude Test Paper 4 Also Read Similar Questions Below : 32 ⇒ The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:504536544 548 ⇒ The HCF and LCM of two numbers is 2 and 70. If the sum of the numbers is 24, find the smallest of the two numbers.14107 12 ⇒ Find the value of LCM (1,2,3,4.....................100)/LCM (51,52,53,.............100)123 4 ⇒ The greatest number that will divide 82, 111 and 140 leaving the same remainder in each case is584731 29 ⇒ Find the LCM of the first seven natural numbers.16884840 420 ⇒ The greatest number by which if 1657 and 2037 are divided the remainders will be 6 and 5 respectively is-----------127235260 305 ⇒ About the number of pairs which have 16 as their HCF and 136 as their LCM, the conclusion can be-only one such pair existsonly two such pairs existmany such pairs exist no such pair exists ⇒ The greatest number of four digits which is divisible by 15, 25, 40 and 75 is:900094009600 9800 ⇒ Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is:4080120 200 ⇒ Three piece of timber 42 m, 49 m and 63 m long have to be divided into planks of the same length. What is the greatest possible length of each plank?7m14m42m 63m ⇒ Three numbers are in the ratio 2:3:5 and their H.C.F. is 8. The numbers are32,48,808,12,2012,18,30 16,24,40 ⇒ The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:31323 33 ⇒ Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.479 13 ⇒ The traffic signals at four road crossings change every 30 seconds, 1 minute, 45 seconds and 75 seconds respectively. If they changed simultaneously at 9:00 am, at what time will they change simultaneously again?9:12 am9:15 am9:20 am 9:30 am ⇒ If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:55/6015/60112/120 11/120 ⇒ A number when divided by 6 leaves a remainder of 5, when divided by 5 leaves a remainder of 4, when divided by 4 leaves a remainder of 3, when divided by 3 leaves a remainder of 2 and when divided by 2 leaves a remainder of 1. Find the number.594929 19 ⇒ The sum of two numbers is 216 and their H.C.F. is 27. The numbers are :27, 18981, 189108, 108 154, 162 ⇒ Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is456 8 ⇒ Ten years ago A was half of B in age. If the ratio of their present ages is 3:4 , what will be the total of their present ages ?20 years30 years35 years None of these ⇒ Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.479 13 ⇒ Harshini has three pieces of thread of length 15m, 18m and 24m. She is asked to cut them into smaller pieces of equal length such that no piece of thread gets wasted. Find the minimum number of smaller threads she will get.197224 15 ⇒ The product of LCM and HCF of two positive integers x and y is 12. How many distinct values can x take?1263 4 ⇒ The greatest 4-digit number which is divisible by 6,8 and 10 is996099999990 9600 ⇒ The ratio of the ages of father and son at present is 6:1. After 5 years the ratio of will become 7:2. The present age of the son is :5 years10 years15 years 20 years ⇒ The HCF of 2 prime numbers istheir producttheir sumone zero ⇒ The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:279283308 318 ⇒ The smallest positive integer which is a common multiple of two prime numbers istheir producttheir sum2 1 ⇒ The HCF and LCM of two numbers are 4 and 60. Which of the following could be those numbers?24,606,4012,20 18,40 ⇒ Find the HCF of 2/3,3/4 and 4/5.1/602/51/12 2/15 |
If the HCF of two numbers is 2 and their LCM is 70 then the numbers are a 2 35 B 4 70 C 6 70 D 14 10
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