If you're seeing this message, it means we're having trouble loading external resources on our website. If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. Complete the following activity to solve the given quadratic equation by factorization method. Activity: x2 + 8x – 20 = 0 x2 + ( __ ) – 2x – 20 = 0 x (x + 10) – ( __ ) (x + 10) = 0 (x + 10) ( ____ ) = 0 x = ___ or x = 2 x2 + 8x – 20 = 0 x2 + 10x – 2x – 20 = 0 ∴ x (x + 10) – 2 (x + 10) = 0 ∴ x (x + 10) – (x – 2) = 0 ∴ x + 10 = 0 or x – 2 = 0 x = – 10 or x = 2 Concept: Solutions of Quadratic Equations by Factorization Is there an error in this question or solution? Solve the following quadratic equation by factorisation. \[\sqrt{2} x^2 + 7x + 5\sqrt{2} = 0\] to solve this quadratic equation by factorisation, complete the following activity. √2 x2 + 7 x + 5 √2 = 0 x(. . . . .) + √2 (. . . . .) = 0 (. . . . .)(x + 2 ) = 0(. . . . .) = 0 or (x + 2 ) = 0 ∴ x = ∴ \[\sqrt{2} x^2 + 7x + 5\sqrt{2} = 0\] \[\sqrt{2} x^2 + 5x + 2x + 5\sqrt{2} = 0\]\[x\left( \sqrt{2}x + 5 \right) + \sqrt{2}\left( \sqrt{2}x + 5 \right) = 0\]\[\left( \sqrt{2}x + 5 \right)\left( x + \sqrt{2} \right) = 0\]\[\left( \sqrt{2}x + 5 \right) = 0 \text{ or } \left( x + \sqrt{2} \right) = 0\]\[ \therefore x = \frac{- 5}{\sqrt{2}} \text{ or } x = - \sqrt{2}\] \[ \therefore \frac{- 5}{\sqrt{2}} \text{ and } - \sqrt{2} \text{ are the roots of the equation } .\] Concept: Solutions of Quadratic Equations by Factorization Is there an error in this question or solution? |