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Given: A can do a piece of work in 4 hours. B and C together can do it in 3 hours. A and C together can do it in 2 hours. Concept Used: Work done = 1/Time Or Work done = Efficiency × Time Calculation: A can do a piece of work in 4 hours. A's 1 day work = 1/4 A and C together can do it in 2 hours. (A + C)'s 1 day work = 1/2 C's 1 day work = 1/2 - 1/4 = 1/4 B and C together can do it in 3 hours. (B + C)'s 1 day work = 1/3 B's 1 day work = 1/3 - 1/4 = 1/12 Time taken by B to complete the work = 12 days ∴ Time taken by B to complete the work is 12 days.
A can do a piece of work in 4 hours. B and C together can do it in 3 hours. A and C together can do it in 2 hours. Total work done = LCM of days = 12 units Efficiency of A = 3 units Efficiency of A + C = 6 units Efficiency of C = 6 - 3 = 3 units Efficiency of B + C = 4 units Efficiency of B = 4 - 3 = 1 units Time taken by B to complete the work = 12/ 1 = 12 days ∴ Time taken by B to complete the work is 12 days. India’s #1 Learning Platform Start Complete Exam Preparation
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Can do a piece of work in 4 hours B and C together can do it in 3 hours while A and C together can do it in 2 hours how long will b?
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