Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Text Solution <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V02_C09_E01_342_O01.png" width="30%"><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V02_C09_E01_342_O02.png" width="30%"><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V02_C09_E01_342_O03.png" width="30%"><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V02_C09_E01_342_O04.png" width="30%"> Answer : C Solution : We have, `(1)/(f)=(1)/(v)-(1)/(u) Rightarrow (1)/(f)=(1)/(-20)-(-(1)/(40))` <br> `=(-2+1)/(40)=-(1)/(40)` <br> or f=-40cm <br> Power of lens, `P=(200)/(0.40)=-2.5D` |