What number must be added to 16 26 and 40 so that the resulting numbers may be in continued proportion?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

What number must be added to each of the numbers 16, 26 and 40 so that the resulting numbers may be in continued proportion?

Let x be added to each number then16 + x, 26 + x and 40 + xare in continued proportion.⇒ `(16 + x)/(26 + x) = (26 + x)/(40 + x)`Cross Multiplying(16 + x) (40 + x) = (26 + x) (26 + x)

⇒ 640 + 16x + 40x + x2 = 676 + 26x + 26x + x2

⇒ 640 + 56x + x2 = 676 + 52x + x2
⇒ 56x + x2 - 52x - x2 = 676 - 640⇒ 4x = 36⇒ x = `(36)/(4)` = 9

∴ 9 is to be added.

Concept: Concept of Proportion

Is there an error in this question or solution?

What number must be added to each of the number 16, 26 and 40 so that the resulting numbers may be in continued proportion?

Let the number added be x.∴ (16 + x) : (26 + x) :: (26 + x) (40 + x) 16 +x = 26 +x 26 + x 40 + x (162 + x)(40 + x) = (26 + x2 ) 640 + 16x + 40x + x2 = 676 + 52x + x2 56x - 52x = 676 - 640

4x = 36

x = 9
Thus, the required number which should be added is 9.

Concept: Concept of Proportion

Is there an error in this question or solution?