What are the possible dimensions of constructing a triangle of perimeter of 12cm?

Question 23 Exercise 10.1

Answer:

Solution:

Let the length of the third side be x cm.

The length of the other two sides is 12 cm and 14 cm.

Now, the Perimeter of triangle = 36 cm

$12+14+x=36$

$26+x=36$

$x=36-26=10$

Thus, the length of third side is 10 cm.

Video transcript

Hello students, welcome to the Lido learning. So here the question is two supplementary angles are Phi x minus 82 degrees + 4 x + 73 degrees. So here we have to find the value of the X. So let us write it starts the answer. So here solution is supplementary angles are 180 degrees, right? So here the equation is 5X minus 82 degrees plus 44 x + 73 degrees is 180 degrees. So you're freaking observe 9x minus 9 9 x minus 9 is equal to 180 degrees. So 9 x if we sent to the right-hand side we get 9x is equals to 1 89. So here if we send mine from multiplying to the right-hand side dividing. Sorry. Sorry. Sorry dividing X equals to one eighty-nine by nine is equal to the answer the final answer we get the x value is 21 degrees. Thank you for watching our video. A subscriber to our Channel and feel free to ask doubts in the comment section below. Thank you.

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We will discuss here how to find the perimeter of a triangle. We know perimeter of a triangle is the total length (distance) of the boundary of a triangle.

Perimeter of a triangle is the sum of lengths of its three sides.

For example, perimeter of the ∆PQR = PQ + QR + RP

The perimeter of a triangle ABC

= AB + BC + CA

= 2 cm + 4 cm + 3 cm,

(add the length of each side of the triangle).

= 9 cm

Perimeter of the triangle = Sum of the sides.

Let us consider some of the examples on perimeter of a triangle:

1. Find the perimeter of a triangle having sides 3 cm, 8 cm and 6 cm.

Solution:

Perimeter of a triangle

= Sum of all the three sides

= AB + BC + AC

= 3 cm + 8 cm + 6 cm

= 17 cm

2. Find the perimeter of the triangle PQR whose sides are 4 cm, 6 cm and 8 cm.

Solution:

In the figure PQ = 4 cm, PR = 6 cm and QR = 8 cm

The perimeter of the rectangle PQR

= 4 cm + 6 cm + 8 cm

= 18 cm

3. Find the perimeter of an equilateral triangle whose one side is 5 cm.

Solution:

A triangle in which all the sides are equal is called an equilateral triangle.

Perimeter of the equilateral triangle = 3 × side

= 3 × 5 cm

= 15 cm

Thus, perimeter = 15 cm.

4. Find the perimeter of a triangle whose length of three sides are 8 cm, 11 cm, 13 cm.

Solution:

To find the perimeter of the triangle, we add all the sides together.

Perimeter of a triangle

= Sum of all the three sides

= 8 cm + 11 cm + 13 cm

= 32 cm

5. Find the perimeter of a triangle whose sides are 5 cm, 2 cm and 3 cm.

Solution:

Perimeter of the triangle is the sum of the lengths of its sides.

Perimeter = 5 cm + 2 cm + 3 cm

Thus, perimeter = 10 cm.

6. Find the perimeter of each triangle.

Solution:

(i) Perimeter of ∆XYZ = 5.5 cm + 6 cm + 6 cm = 17.5 cm

(ii) Perimeter of ∆ABC = 8 cm + 6 cm + 6 cm = 20 cm

(iii) Perimeter of ∆PQR = 4 cm + 3 cm + 5 cm = 12 cm

7. Find the perimeter of the given shapes.

Solution:

(i) Perimeter = PQ + QR + RS + ST + TU + UV + VP

= 2.5 cm + 3 cm + 2 cm + 3 cm + 2.5 cm + 4 cm + 4 cm

= 21 cm

(ii) Perimeter = PQ + QR + RS + SP

= 4 cm + 4 cm + 4 cm + 4 cm

= 16 cm

(iii) Perimeter = PQ + QR + RS + ST + TP

= 7 cm + 6 cm + 4 cm + 3 cm + 5 cm

= 25 cm

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