15. . Two conducting rods A and B of same length and cross sectional area are connected (i) In series (ii) In parallel as shown. In both combination a temperature difference of 100°C is maintained. If thermal conductivity of A is 3K and that of B is K then the ratio of heat current flowing in parallel combination to that flowing in series combination is- A 3K B 100°C 0°C 100°C 3K K 0°C (i) (ii) 16 1 (1) (2) 3 16 (3) (4) 3 3
The rate of heat transfer is given by dQdt=kA∆Tl. Now series the conductivity will be K1K2K1+K2=3k24k=34k and for parallel connection the conductivity will be K1+k2=4k. No we can see from the conduction equation that the heat transfer is proportion to the conductivity, so the ratio will be equal to the ratio of the conductivity which is 344=316
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Two conducting rods A and B of same length and cross sectional area are connected
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