The sum of all two digit numbers which, when divided by 4, yield unity as a remainder is

10. The sum of all two-digit numbers which when divided by 4 yield unity as remainder i (a) 1012 (b) 1021 (c) 1201 (d) 1210

Siddhant Saxena 2019-09-19 19:39:28

Thanks

Shivangi Mishra 2019-09-14 11:43:16

kindly try to change the background theme.

Yashraj 2019-09-06 22:21:24

Excellent

Sr 2019-07-20 16:40:28

Excellent

Preetam 2016-10-14 01:28:02

Thanks

Page 2

Subhrangshu Bhowmik 2018-11-29 20:16:21

Good

Johnd371 2017-04-09 01:03:13

Someone essentially help to make seriously posts I would state. This is the very first time I frequented your web page and thus far? I surprised with the research you made to make this particular publish incredible. Magnificent job! abebedbffbdd

Johnd400 2016-06-24 11:34:30

I do believe all of the ideas you've offered for your post. They are really convincing and will definitely work. Still, the posts are very quick for newbies. May just you please extend them a little from next time? Thank you for the post. dbeecdgckeae

Page 3

Question 8

Answer

Let the sum of n terms of the G.P. be 315.

It is known that,

It is given that the first term a is 5 and common ratio r is 2.

∴Last term of the G.P = 6th term = ar6 – 1 = (5)(2)5 = (5)(32) = 160

Thus, the last term of the G.P. is 160.

Recently Viewed Questions of Class 11 Mathematics

Q:-
Find the sum of integers from 1 to 100 that are divisible by 2 or 5.
Q:-
What will Rs 500 amounts to in 10 years after its deposit in a bank which pays annual interest rate of 10% compounded annually?
Q:-
A wheel makes 360 revolutions in one minute. Through how many radians does it turn in one second?
Q:-
If A and G be A.M. and G.M., respectively between two positive numbers, prove that the numbers are
.
Q:-
If the pth, qth and rth terms of a G.P. are a, b and c, respectively. Prove that aq-rbr-pcp-q=1
Q:-
Prove the following by using the principle of mathematical induction for all n ∈ N:

n (n + 1) (n + 5) is a multiple of 3.
Q:-
The 5th, 8th and 11th terms of a G.P. are p, q and s, respectively. Show that q2 = ps.
Q:-
If the sum of first p terms of an A.P. is equal to the sum of the first q terms, then find the sum of the first (p + q) terms.
Q:-
Let S be the sum, P the product and R the sum of reciprocals of n terms in a G.P. Prove that P2Rn = Sn
Q:-
Insert five numbers between 8 and 26 such that the resulting sequence is an A.P.

Last updated at Sept. 3, 2021 by

This video is only available for Teachoo black users

Introducing your new favourite teacher - Teachoo Black, at only ₹83 per month

Misc 6 Find the sum of all two digit numbers which when divided by 4, yields 1 as remainder. Two digit numbers are 10,11,12,13, .98,99 Finding minimum number in 10,11,12,13, .98,99 which when divided by 4 yields 1 as remainder 10/4 = 22/4 11/4 = 23/4 12/4 = 3 13/4 = 31/4 So the sequence will start from 13 Finding maximum number in 10,11,12,13, .98,99 which when divided by 4 yields 1 as remainder 99/4 = 243/4 98/4 = 242/4 97/4 = 241/4 So the sequence will end at 97 Thus, the sequence starts with 13 and ends with 97 Thus, the two digit numbers which are divisible by 4 yield 1 as remainder are 13, 17, 21, 25, 93,97. This forms an A.P. as difference of consecutive terms is constant. 13, 17, 21, 25, 93,97. First term a = 13 Common difference d = 17 13 = 4 Last term l = 97 First we calculate number of terms in this AP We know that an = a + (n 1)d where an = nth term , n = number of terms, a = first term , d = common difference Here, an = last term = l = 97 , a = 13 , d = 4 Putting values 97 = 13 + (n 1)4 97 13 = (n 1)4 84 = (n 1)4 84/4 = (n 1) 21 = n 1 21 + 1 = n 22 = n n = 22 For finding sum, we use the formula Sn = n/2 [a + l] Here, n = 22 , l = 97 & a = 13 S22 = 22/2 [13 + 97] = 11 [110] = 1210 Hence, sum of all two digit numbers which when divided by 4, yields 1 as remainder is 1210