Lakshmi tosses two coins simultaneously the probability that she gets atmost one head is

When two coins are tosses simultaneously , the possiuble outcomes are {(H,H)(H,T)(T,H)(T,T)} 

n(s)=4 

The outcomes favourable to the event E,' at most one head are {(T,H)(H,T)(T,T)} 

So, the number of outcomes favourable to E is 3=n(E) 

Therefore, p(E)=`(n(E))/(n(s))=3/4`