If A and B are two events such that P(A) = 1/3, P(B) = 1/4,P(A∩B) = 1 12 then P(A/B)

Try the new Google Books

Check out the new look and enjoy easier access to your favorite features

Page 2

Text Solution

`1/12``3/4``1/4``3/16`

Solution : Here,`P(A)=1/2,P(B)=1/3andP(A//B)=1/4` <br> `becauseP(A//B)=(P(AcapB))/(P(B))` <br> `rArrP(AcapB)=P(A//B)cdotP(B)=1/4cdot1/3=1/12` <br> Now, `P(A'capB')=1-P(AcupB)` <br> `=1-[P(A)+P(B)-P(AcapB)]` <br> `=1-[1/2+1/3-1/12]=1-[(6+4-1)/12)]` <br> `=1-9/12=3/12=1/4`

Try the new Google Books

Check out the new look and enjoy easier access to your favorite features

Page 2