Calculate the power output of a 14-mg fly as it walks straight up a windowpane at 2.3 cm/s.

Problem 45P

Problem 45P

Calculate the power output of a 1.4-g fly as it walks straight tip a windowpane at 2.3 cm/s.

Step-by-Step Solution:

Step 1 of 2

We have to calculate the power output of a 1.4-g fly as it walks straight through a windowpane at 2.3 cm/s.

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The answer to “Calculate the power output of a 1.4-g fly as it walks straight tip a windowpane at 2.3 cm/s.” is broken down into a number of easy to follow steps, and 18 words. This full solution covers the following key subjects: calculate, fly, output, power, straight. This expansive textbook survival guide covers 32 chapters, and 3833 solutions. Since the solution to 45P from 7 chapter was answered, more than 1029 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 45P from chapter: 7 was answered by , our top Physics solution expert on 07/27/17, 10:59AM. This textbook survival guide was created for the textbook: Physics with MasteringPhysics, edition: 4. Physics with MasteringPhysics was written by and is associated to the ISBN: 9780321541635.

Calculate the power output of a 14-mg fly as it walks straight up a windowpane at 2.3 cm/s.

Calculate the power output of a 14-mg fly as it walks straight up a windowpane at 2.3 cm/s.
Calculate the power output of a 14-mg fly as it walks straight up a windowpane at 2.3 cm/s.

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Calculate the power output of a 14-mg fly as it walks straight up a windowpane at 2.3 cm/s.

University of Michigan - Ann Arbor

We don’t have your requested question, but here is a suggested video that might help.

Calculate the power output of a $14-\mathrm{mg}$ fly as it walks straight upa windowpane at 2.3 $\mathrm{cm} / \mathrm{s} .$

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  • Thread starter Precursor
  • Start date Feb 6, 2010

Calculate the power output of a 1.8-g spider(the black dot) as it walks up a windowpane at 2.3 cm/s. The spider walks on a path that is at [tex]25^{o}[/tex] to the vertical as illustrated below. http://img19.imageshack.us/img19/4107/spiderl.jpg [Broken]

Homework Equations

P = W/t F = mg

The Attempt at a Solution

P= W/t = Fd/t = Fv cos [tex]\theta[/tex] = mgv cos 25 = (0.0018 kg)(9.81 m/s^2)(0.023 m/s) cos25 = 0.00037 W. Is this correct?

Thanks

Last edited by a moderator: May 4, 2017

Answers and Replies

While calculating the power you have not considered the angle given in the problem.
So W = F*v*cos(theta)

I have actually just editted my post after realizing this.