At what rate percent per annum compound interest will 10000 amounts to 13310 in 3 years?

Correct Answer:

Description for Correct answer:

\( \Large A=P \left(1+\frac{1}{100}\right)^{3}\)\( \Large \frac{1331}{1000}= \left(1+\frac{R}{100}\right)^{3}\)\( \Large\left(\frac{11}{10}\right)^{3}= \left(1+\frac{R}{100}\right)^{3} \)\( \Large \frac{11}{10}-1=\frac{R}{100} \)\( \Large \frac{R}{100}=\frac{1}{10} \)

R= 10%

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