The difference between the squares of two consecutive numbers is 31. Find the numbers. Let the numbers be x and x + 1 .According to the question, \[(x + 1 )^2 - x^2 = 31\]\[\text{ or }x^2 + 2x + 1 - x^2 = 31\]\[\text{ or }2x = 31 - 1\]\[\text{ or }x = \frac{30}{2}\]or x = 15 Thus, the numbers are 15 and 16 . Concept: Equations Reducible to the Linear Form Is there an error in this question or solution? > 13 |