If the product of two zeroes of the polynomial fx=2x3+6x2−4x+9 is 3, then its third zero is

Let αβγ  be the zeros of polynomial f(x) = 2x3 + 6x2 − 4x + 9 such that `alphabeta=3`

We have,

`alpha ß y= - (text{coefficient of x})/(text{coefficient of } x^2)`

`=(-9)/2`

Putting `alphabeta` in `alpha beta y`, we get

`alpha beta y = (-9)/2`

`3 y = (-9)/2xx1/3`

`y = (-3)/2`

Therefore, the value of third zero is `(-3)/2`

Hence, the correct alternative is (b).