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10 Questions 10 Marks 10 Mins
Given:
A can do a piece of work in 4 hours.
B and C together can do it in 3 hours.
A and C together can do it in 2 hours.
Concept Used:
Work done = 1/Time Or
Work done = Efficiency × Time
Calculation:
A can do a piece of work in 4 hours.
A's 1 day work = 1/4
A and C together can do it in 2 hours.
(A + C)'s 1 day work = 1/2
C's 1 day work = 1/2 - 1/4 = 1/4
B and C together can do it in 3 hours.
(B + C)'s 1 day work = 1/3
B's 1 day work = 1/3 - 1/4 = 1/12
Time taken by B to complete the work = 12 days
∴ Time taken by B to complete the work is 12 days.
A can do a piece of work in 4 hours.
B and C together can do it in 3 hours.
A and C together can do it in 2 hours.
Total work done = LCM of days = 12 units
Efficiency of A = 3 units
Efficiency of A + C = 6 units
Efficiency of C = 6 - 3 = 3 units
Efficiency of B + C = 4 units
Efficiency of B = 4 - 3 = 1 units
Time taken by B to complete the work = 12/ 1 = 12 days
∴ Time taken by B to complete the work is 12 days.
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