When an object is placed at a distance of 40 cm from a lens the image is formed at the same distance from the lens find the power of the lens?

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Text Solution

<img src="//d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V02_C09_E01_342_O01.png" width="30%"><img src="//d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V02_C09_E01_342_O02.png" width="30%"><img src="//d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V02_C09_E01_342_O03.png" width="30%"><img src="//d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V02_C09_E01_342_O04.png" width="30%">

Answer : C

Solution : We have, `(1)/(f)=(1)/(v)-(1)/(u) Rightarrow (1)/(f)=(1)/(-20)-(-(1)/(40))` <br> `=(-2+1)/(40)=-(1)/(40)` <br> or f=-40cm <br> Power of lens, `P=(200)/(0.40)=-2.5D`