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Juanelle B. Can you please help me solve this problem> If each of the dimensions of a rectangle is increased by 100% , by what percent is the area increased.
3 Answers By Expert Tutors
Bob A. answered • 12/07/13
20 Years Making Science and Maths Understandable and Interesting!
There is an important difference in the ways the new area could possibly be stated.
The new area is 4 times what it was before.
So the new area is four times the old area of LW
But the increase in area is 300%
Increase is looking for the difference between the old and new.
So the increase in area is 3 times what the old area was
or the increase in area is 300%.
Since according to your question you are asked for the percent increase,
the answer would be "the area is increased by 300 precent".
Nataliya D. answered • 12/06/13
Patient and effective tutor for your most difficult subject.
100% = 1 A = length * width "... if each of the dimensions of a rectangle is increased by 100% ..."
Let length of new rectangle be "l1" and width - "w1"
l1 = l + l * 100% = l + l * 1 = 2l
w1 = w + w * 100% = w + w * 1 = 2w
A1 = 2l * 2w = 4lw =
lw + 3lw =
A + 3A =
A + 300% * A
Thus, the area is increased by 300%
Vivian L. answered • 12/06/13
Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACH
Increasing anything by 100% is doubling it.
4(Area)=[2(length)][2(width)]
Let's try a hypothetical example.
A rectangle is 4 units x 3 units.
Its area is 12 units-squared.
We will increase both dimensions by 100%. We will double each of these.
It is now 8 units x 6 units.
Its area is 48 units-squared.
Its increase is 4x2=(2x2+2x2)
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15 Questions 30 Marks 10 Mins
Given:
Each side of the Rectangle increases by 20 %
Concept Used:
Concept of percentage. It is calculated on the basis of 100.
For example, x% means x out of 100.
Area of rectangle = Length × Breadth
Calculation:
Let, the length of the rectangle be l and the breadth be b
According to the Question,
Each side increases by 20%
⇒ New length = (120/100) × l = (1.2 × l) and new breadth = (120/100)b = 1.2b
Initial area = l × b
new area with new side = (1.2 × l) × (1.2b) = 1.44 × lb
\(Net\;change = \frac{({1.44 - 1}) \times lb}{{lb}} × 100 = 44\;\% \;\;\)
∴ The percentage in area is 44%.
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