The formula given below can be used to find the difference between compound interest and simple interest for two years.
The above formula is applicable only in the following conditions.
1. The principal in simple interest and compound interest must be same.
2. Rate of interest must be same in simple interest and compound interest.
3. In compound interest, interest has to be compounded annually.
Example 1 :
The difference between the compound interest and simple interest on a certain investment at 10% per year for 2 years is $631. Find the value of the investment.
Solution :
The difference between compound interest and simple interest for 2 years is 631.
Then we have,
P(R/100)2 = 631
Substitute R = 10.
P(10/100)2 = 631
P(1/10)2 = 631
P(1/100) = 631
Multiply both sides by 100.
P = 631 x 100
P = 63100
So, the value of the investment is $63100.
Example 2 :
The compound interest and simple interest on a certain sum for 2 years is $ 1230 and $ 1200 respectively. The rate of interest is same for both compound interest and simple interest and it is compounded annually. What is the principal ?
Solution :
To find the principal, we need rate of interest. So, let us find the rate of interest first.
Step 1 :
Simple interest for two years is $1200. So interest per year in simple interest is $600.
So, C.I for 1st year is $600 and for 2nd year is $630.
(Since it is compounded annually, S.I and C.I for 1st year would be same)
Step 2 :
When we compare the C.I for 1st year and 2nd year, it is clear that the interest earned in 2nd year is 30 more than the first year.
Because, in C.I, interest $600 earned in 1st year earned this $30 in 2nd year.
It can be considered as simple interest for one year.
That is, principle = 600, interest = 30
I = PRT/100
30 = (600 x R x 1)/100
30 = 6R
Divide both sides by 6.
5 = R
So, R = 5%.
Step 3 :
The difference between compound interest and simple interest for two years is
= 1230 - 1200
= 30
Then we have,
P(R/100)2 = 30
Substitute R = 5.
P(5/100)2 = 30
P(1/20)2 = 30
P(1/400) = 30
Multiply both sides by 400.
P = 30 x 400
P = 12000
So, the principal is $12000.
Kindly mail your feedback to
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
We will discuss here how to find the difference of compound interest and simple interest.
If the rate of interest per annum is the same under both simple interest and compound interest then for 2 years, compound interest (CI) - simple interest (SI) = Simple interest for 1 year on “Simple interest for one year”.
Compound interest for 2 years – simple interest for two years
= P{(1 + \(\frac{r}{100}\))\(^{2}\) - 1} - \(\frac{P × r × 2}{100}\)
= P × \(\frac{r}{100}\) × \(\frac{r}{100}\)
= \(\frac{(P × \frac{r}{100}) × r × 1}{100}\)
= Simple interest for 1 year on “Simple interest for 1 year”.
Solve examples on difference of compound interest and simple
interest:
1. Find the difference of the compound interest and simple interest on $ 15,000 at the same interest rate of 12\(\frac{1}{2}\) % per annum for 2 years.
Solution:
In case of Simple Interest:
Here,
P = principal amount (the initial amount) = $ 15,000
Rate of interest (r) = 12\(\frac{1}{2}\) % per annum = \(\frac{25}{2}\) % per annum = 12.5 % per annum
Number of years the amount is deposited or borrowed for (t) = 2 year
Using the simple interest formula, we have that
Interest = \(\frac{P × r × 2}{100}\)
= $ \(\frac{15,000 × 12.5 × 2}{100}\)
= $ 3,750
Therefore, the simple interest for 2 years = $ 3,750
In case of Compound Interest:
Here,
P = principal amount (the initial amount) = $ 15,000
Rate of interest (r) = 12\(\frac{1}{2}\) % per annum = \(\frac{25}{2}\) % per annum = 12.5 % per annum
Number of years the amount is deposited or borrowed for (n) = 2 year
Using the compound interest when interest is compounded annually formula, we have that
A = P(1 + \(\frac{r}{100}\))\(^{n}\)
A = $ 15,000 (1 + \(\frac{12.5}{100}\))\(^{2}\)
= $ 15,000 (1 + 0.125)\(^{2}\)
= $ 15,000 (1.125)\(^{2}\)
= $ 15,000 × 1.265625
= $ 18984.375
Therefore, the compound interest for 2 years = $ (18984.375 - 15,000)
= $ 3,984.375
Thus, the required difference of the compound interest and simple interest = $ 3,984.375 - $ 3,750 = $ 234.375.
2. What is the sum of money on which the difference between simple and compound interest in 2 years is $ 80 at the interest rate of 4% per annum?
Solution:
In case of Simple Interest:
Here,
Let P = principal amount (the initial amount) = $ z
Rate of interest (r) = 4 % per annum
Number of years the amount is deposited or borrowed for (t) = 2 year
Using the simple interest formula, we have that
Interest = \(\frac{P × r × 2}{100}\)
= $ \(\frac{z × 4 × 2}{100}\)
= $ \(\frac{8z}{100}\)
= $ \(\frac{2z}{25}\)
Therefore, the simple interest for 2 years = $ \(\frac{2z}{25}\)
In case of Compound Interest:
Here,
P = principal amount (the initial amount) = $ x
Rate of interest (r) = 4 % per annum
Number of years the amount is deposited or borrowed for (n) = 2 year
Using the compound interest when interest is compounded annually formula, we have that
A = P(1 + \(\frac{r}{100}\))\(^{n}\)
A = $ z (1 + \(\frac{4}{100}\))\(^{2}\)
= $ z (1 + \(\frac{1}{25}\))\(^{2}\)
= $ z (\(\frac{26}{25}\))\(^{2}\)
= $ z × (\(\frac{26}{25}\)) × (\(\frac{26}{25}\))
= $ (\(\frac{676z}{625}\))
So, the compound interest for 2 years = Amount – Principal
= $ (\(\frac{676z}{625}\)) - $ z
= $ (\(\frac{51z}{625}\))
Now, according to the problem, the difference between simple and compound interest in 2 years is $ 80
Therefore,
(\(\frac{51z}{625}\)) - $ \(\frac{2z}{25}\) = 80
⟹ z(\(\frac{51}{625}\) - \(\frac{2}{25}\)) = 80
⟹ \(\frac{z}{625}\) = 80
⟹ z = 80 × 625
⟹ z = 50000
Therefore, the required sum of money is $ 50000
● Compound Interest
Compound Interest
Compound Interest with Growing Principal
Compound Interest with Periodic Deductions
Compound Interest by Using Formula
Compound Interest when Interest is Compounded Yearly
Compound Interest when Interest is Compounded Half-Yearly
Compound Interest when Interest is Compounded Quarterly
Problems on Compound Interest
Variable Rate of Compound Interest
Practice Test on Compound Interest
● Compound Interest - Worksheet
Worksheet on Compound Interest
Worksheet on Compound Interest with Growing Principal
Worksheet on Compound Interest with Periodic Deductions8th Grade Math Practice
From Difference of Compound Interest and Simple Interest to HOME PAGE
Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.
Share this page: What’s this? |