In the given problem, the sum of two angles of a triangle is equal to its third angle. We need to find the measure of the third angle.
Thus, it is given, in ΔABC A+B+C ........(1) Now, according to the angle sum property of the triangle, we get, ∠A +∠B + ∠C = 180° ∠C + ∠C = 180° (Using 1) 2∠C = 180° `∠C = (180°)/2` ∠C = 90° Therefore, the measure of the third angle is ∠C = 90°. |