Pola berlian berongga dalam ahli penugasan python

Dalam program python ini pertama-tama kita membaca baris dari pengguna. Di sini baris menunjukkan jumlah baris yang akan dicetak dalam satu pola segitiga dari pola Hollow Diamond. Diberi nilai baris 5, jumlah total garis dalam pola belah ketupat adalah 9

Kode Sumber Python. Pola Berlian Berongga

# Hollow Diamond pattern # Reading number of row row = int(input('Enter number of row: ')) # Upper part of hollow diamond for i in range(1, row+1): for j in range(1,row-i+1): print(" ", end="") for j in range(1, 2*i): if j==1 or j==2*i-1: print("*", end="") else: print(" ", end="") print() # Lower part of hollow diamond for i in range(row-1,0, -1): for j in range(1,row-i+1): print(" ", end="") for j in range(1, 2*i): if j==1 or j==2*i-1: print("*", end="") else: print(" ", end="") print()

Keluaran

Enter number of row: 8 * * * * * * * * * * * * * * * * * * * * * * * * * * * * _

Kode berikut akan berfungsi untuk sejumlah baris tertentu

# Python 3 program to print a hallow diamond pattern given N number of rows alphabets = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U','V', 'W', 'X', 'Y', 'Z'] # Diamond array diamond = [] rows = -1 # Prompt user to enter number of rows while rows < 1 or rows > 26: rows = int(input("Enter number of rows N: ")) for i in range(0, rows): # Add letters to the diamond diamond.append("") for j in range(0, rows - i): diamond[i] += " " diamond[i] += alphabets[i]; if alphabets[i] != 'A': # Put spaces between letters for j in range(0, 2 * i - 1): diamond[i] += " " diamond[i] += alphabets[i] # Print the first part of the diamond print(diamond[i]) # Print the second part of the diamond for i in reversed(range(0, rows - 1)): print(diamond[i])# Berlian. py N = int(input()) left = N-1 mid = -1 ch = 'A' print(' '*left, ch, sep='') for _ in range(N-1). kiri -= 1     pertengahan += 2     ch = chr(ord(ch)+1)     print(' '*left, ch, ' '*mid, ch, sep='')      for _ in range(N-2). kiri += 1     tengah -= 2     ch = chr(ord(ch)-1)     print(' '*kiri, ch, ' '*mid, ch, sep='') kiri += 1 ch = 'A' cetak

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