    # If all the sides of a cuboid are increased by 20 then by what percentage does its volume increase

 Hello Prasad ! Formula for Volume of cuboid is , (length × breadth × height) cubic units. So , if length is  increased by 20% which means new length is 1.2 time of old length , similarly , new breadth will become 1.1 time more and height will become 0.95 times of old height , as it decreased. So now , new volume will become , 1.2 * length × 1.1*breadth × 0.95*height , 1.254 * length × breadth × height , Which means it get increased by 25.4 % Hope it helps ! Busting myths around Online MBA Apply FREE Webinar! Interact with Dr. Sanjay Verma, e-PGP chair at IIM- Ahmedabad, and Mr. ARKS Srinivas, IIM-C Alumnus and MBA Mentor for 25+ Years. AttainU- Full Stack Developer... Apply Apply for Full Stack Developer Course With Placement Specializations in Online MBA Apply FREE Webinar! Interact with Career Coaches, Domain Experts and learn more about specialized MBA & general MBA, future scope, and more. Apply FREE Webinar! Interact with experts from IU Germany & learn more about placements, faculty & student support, and more. Apply Earn an MBA degree from India's Top University Great Lakes PGPM & PGDM 2023 ... Apply World Class Full Time & Visiting Faculty | 31.1 LPA Avg. CTC for Top 10% of PGPM 2022 View All Application Forms 150M+ Students 30,000+ Colleges 500+ Exams 1500+ E-books Try the new Google BooksCheck out the new look and enjoy easier access to your favorite features Given:Increase in length of cuboid = 20%Increase in breadth of cuboid = 30%Increase in height of cuboid = No changeFormula Used:Volume of a Cuboid = l × b × hwhere,l = Length of the cuboid b = Breadth of the cuboidh = Height of the cuboidCalculation:According to the question,Initial volume of the cuboid = l × b × h = lbhAgain, According to the question,New length of cuboid = (120/100) × l⇒ (6/5) × l & New breadth of cuboid = (130/100) × b⇒ (13/10) × bSo, New volume of cuboid = (6/5) × l × (13/10) × b × h⇒ (6/5) × (13/10) × lbh⇒ (78/50) × lbh ⇒ (156/100) × Intial volume of the cuboidNow, Required percentage = {(New volume - Initial volume)/Initial volume} × 100%⇒ [{(156/100) × lbh - lbh}/lbh] × 100%⇒ {(156 - 100)/100} × 100%⇒ (56/100) × 100%⇒ 56%∴ The new volume of the cuboid is 56% greater than the initial volume of the cuboid.We can use successive percentage method to solve thisWhen there is increase of a% and b% then the overall percentage change is a + b + ab/100As Volume of cuboid depends on length, breadth and height but there is no change in height then the change in volume will only depend on two factors (i.e. length and breadth)Percentage change in volume = 20 + 30 + (20 × 30)/100 = 50 + 6 = 56%∴ The new volume of the cuboid is 56% greater than the initial volume of the cuboid. If length, breadth and height of a cuboid are increased by 20 %, what is the percentage increase in the the total surface area of cuboid? [3 MARKS] Open in App Suggest Corrections1 