Text Solution Answer : 4 Solution : the enrgy associated with incident photon `(hc)/( lambda)` <br> ` rArr E = (6.6 xx 10^(-34) xx 3 xx 10^8)/( 300 xx 10^(-90) J` <br> ` E` in `eV = ( 6.6 xx 10^(-34) xx .3 xx 10^8)/( 300 xx 10^(-9) xx 1.6 xx 10^(-19)) = 4. 16 eV` <br> So, number fo metal showing phote -electric effects whill be (4) , i, e, Li, na, K, Mg, . |