At what temperature will oxygen molecules have same root mean square speed as hydrogen molecules at 200 Kelvin?

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Answer

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4800 K3600 K2400 K300 K.

Answer : A

Solution : Since root mean square velocity of oxygen =rms value of hydrogen <br> `therefore sqrt((3RT_(0))/(M_(0)))=sqrt((3RT_(H))/(M_(H)))` <br> `rArr T_(0) =T_(H) cdot (M_(0))/(M_(H))=300xx(32)/(2)=4800 k` <br> Thus, correct choice is (a).